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Mass vs Weight

A man of mass...

Question

A man of mass $m$ is standing on weighing machine in an elevator accelerating upwards with an acceleration $a$ . What will be the reading of weighing machine?

m (g - a) N

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m (g + a) N

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\frac{m}{(g - a)} N

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\frac{m}{(g + a)} N

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Solution

The correct option is B $m (g + a) N$

Free body diagram w.r.t. a observer from ground.
Using Newton's second law of motion,
$N - m g = m a$
So, $N = m a + m g = m (g + a) N$

As we know weighing machine measures normal reaction
So reading of machine will be
$m (g + a) N$

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Mass vs Weight

Standard XII Physics

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A man of mass m is standing on weighing machine in an elevator accelerating upwards with an acceleration a. What will be the reading of weighing machine?

The correct option is B m(g+a) N Free body diagram w.r.t. a observer from ground. Using Newton's second law of motion, N−mg=ma So, N=ma+mg=m(g+a) N As we know weighing machine measures normal reaction So reading of machine will be m(g+a) N

A man of mass $m$ is standing on weighing machine in an elevator accelerating upwards with an acceleration $a$ . What will be the reading of weighing machine?

The correct option is B $m (g + a) N$

Free body diagram w.r.t. a observer from ground.
Using Newton's second law of motion,
$N - m g = m a$
So, $N = m a + m g = m (g + a) N$

As we know weighing machine measures normal reaction
So reading of machine will be
$m (g + a) N$