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Question

A man raises a box of mass 50 kg to a height of 2 m in 2 minutes, while another man raises the same box to the same height in 5 minutes. What is the ratio of work done by them ?

A
1:1
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B
2:1
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C
1:2
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D
4:1
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Solution

The correct option is C 1:1
Work=Fscosθ
where, F is the force applied, s is the displacement, and θ is the angle between the force applied and displacement

Hence, work done is independent of time taken.

In the given cases, θ=0 as the force applied are in the same direction. Also, F=mg
So W=Fs=mgs

In both the cases, mass and displacement are the same.
W=50×10×2=1000J
Hence work done is in the ratio of 1000:1000=1:1.

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