A man raises a box of mass 50kg to a height of 2m in 2minutes, while another man raises the same box to the same height in 5minutes. What is the ratio of work done by them ?
A
1:1
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B
2:1
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C
1:2
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D
4:1
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Solution
The correct option is C1:1 Work=Fscosθ
where, F is the force applied, s is the displacement, and θ is the angle between the force applied and displacement
Hence, work done is independent of time taken.
In the given cases, θ=0∘ as the force applied are in the same direction. Also, F=mg
So W=Fs=mgs
In both the cases, mass and displacement are the same. W=50×10×2=1000J