Question

A man's age is six times the age of his son. In six years, the father's age will be three times of the son's age. The age of the father and the son are respectively:

• A. $18$ years and $3$ years
• B. $30$ years and $5$ years
• C. $24$ years and $4$ years
• D. $42$ years and $7$ years

Answer 1

The correct option is C $24$ years and $4$ years

Let the son's present age be $x$.
Then father's present age $=6x$
After $6$ years, son's age $=x+6$ and father's age $=6x+6$
Given, after $6$ years ,father's age $=3\times$( son's age )
$\Rightarrow 6x+6=3(x+6)$
$\Rightarrow 6x+6=3x+18$
$\Rightarrow 3x=12$
$\Rightarrow x=4$
So, son's present age is $4$ years. Father's present age $=6x=24$ years.