wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man standing in a lift falling under gravity releases a ball from his hand. As seen by him, the ball:

A
Falls down
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Remains stationary
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Goes up
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Executes SHM
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Remains stationary
The acceleration of the body "does not" depend on the mass (for freely falling). Hence both man and ball have same acceleration. Hence their velocities at every point would be same. So "Relative" velocity is 0. Hence the ball will always remains stationary as seen by him

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Understanding Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon