Question

A man standing on a spring balance inside a stationary lift measures $60\text{kg}$. The weight of that person if the lift descends with a uniform downward acceleration of $1.8{\text{m/s}}^2$ will be _____$\text{N}$.
$[g=10{\text{m/s}}^2]$

Answer 1

From ground frame of reference,
$Mg-N=Ma$

$\Rightarrow N=M(g–a)$

$\Rightarrow N=60(10-1.8)=492\text{N}$