Solving Simultaneous Linear Equation Using Method of Elimination
A man starts ...
Question
A man starts his job with a certain salary and earns a fixed increment every year. If his salary was ₹15000 after 4 years of service and ₹18000 after 10 years of service, then find his starting salary and annual increment respectively.
A
₹11000, ₹700
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B
₹13000, ₹500
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C
₹13000, ₹700
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D
₹11000, ₹500
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Solution
The correct option is B ₹13000, ₹500 Let starting salary be ₹x and annual increment be ₹y According to the first condition: x + 4y = 15000 ......(i) According to the second condition: x + 10y = 18000 ......(ii) Subtracting (i) from (ii), we get 6y = 3000 y = 500 Substituting y = 500 in equation (i), we get x + (4×500) = 15000 x = 15000 - 2000 x = 13000 Hence, starting salary is ₹13000 and annual increment is ₹500.