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Standard VIII
Mathematics
Compound Variation
A man starts ...
Question
A man starts repaying a loan as first instalment of Rs.
100
. If he increases the instalment by Rs.
5
every month, what amount he will pay in the
30
t
h
instalment.
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Solution
A
.
P
.
with the first term =
100
and common difference =
5
.
30
t
h
=
a
+
(
n
−
1
)
d
⟹
100
+
(
30
−
1
)
5
⟹
100
+
29
×
5
|
i
m
p
l
i
e
s
100
+
145
⟹
245
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