Question

A man throws a ball at height of 10 m at an angle of ${35}^o$ from horizontal. If mass of ball is 0.5 kg and its initial speed is 30 m/s.
$g=-9.8\frac{m}{s^2}$
Calculate the horizontal range of the ball.

• A. 25.11m
• B. 98.77m
• C. 24.57m
• D. 4.66m
• E. 160.52m

Answer 1

Answer: (B)

98.77m

The speed of ball in vertically upwards direction=$30\times sin{35}^{\circ }m/s=17.21m/s$

The net displacement is $=-10m$

Using the equation of motion $s=ut+\frac{1}{2}a{t}^2$

$⟹-10=\left(30sin{35}^{\circ }\right)t-\frac{1}{2}g{t}^2$

$⟹t=4.02s$

The range of the projectile is the horizontal distance distance the ball covers in the time of its flight=$vcos{35}^{\circ }\times t$
$=30\times cos{35}^{\circ }m/s\times 4.02s$

$=98.77m$