A man throws ball with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time ? (Giveng=9.8m/s2)
A
More than 19.6m/s
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B
At least 9.8m/s
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C
Any speed less than 19.6m/s
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D
Only with speed 19.6m/s
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Solution
The correct option is C More than 19.6m/s The correct option is A.
We have t=2s
When the ball is thrown upward the final velocity become zero.
Therefore,
v=u+at
0=u−gt
Here, g is acceleration due to gravity
u=gt
=9.8×2=19.6 m/s
Thus, when he throws a ball with a minimum speed of 19.6m/s in a time interval of 2s.