A man throws ball with the same speed vertically upwards one after the other at an interval of $2$ seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given $g = 9.8 m / s^{2}$ )

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Solution

Acc. to the question, $v = 0$ (final velocity=0)
$\begin{matrix} v = u + a t v = u - g t 0 = u - 9.8 \times 2 u = 19.6 m / s \end{matrix}$
Hence,velocity must be with the speed more than $19.6 m / s$

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A man throws ball with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given g=9.8m/s2)

Acc. to the question, v=0 (final velocity=0)v=u+atv=u−gt0=u−9.8×2u=19.6m/sHence,velocity must be with the speed more than 19.6m/s

A man throws ball with the same speed vertically upwards one after the other at an interval of $2$ seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given $g = 9.8 m / s^{2}$ )

Acc. to the question, $v = 0$ (final velocity=0)
$\begin{matrix} v = u + a t v = u - g t 0 = u - 9.8 \times 2 u = 19.6 m / s \end{matrix}$
Hence,velocity must be with the speed more than $19.6 m / s$