CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the air at any time (Given g=9.8m/s2 )

A
At least 0.8 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Any speed less than 19.6 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Only with speed 19.6 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
More than 19.6 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D More than 19.6 m/s

Interval of ball throw 2 sec
If we want that minimum three (more than two) ball remain in air then
time of flight of first ball be greater than 4 sec.
T> 4 sec
2ug>4 sec u> 19.6 m/s
for u=19.6. First ball will just strike the ground
second ball will be at highest point
Third ball will be at point of projection or at ground


flag
Suggest Corrections
thumbs-up
28
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon