A man travels the first part of his journey at $20$ km/hr and the next at $70$ km/h, covering the entire journey at an average speed of $50$ km/h. What is the ratio of the distance that the covered at $20$ km/h to that he covered at $70$ km/h?

4 : 21

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3 : 22

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1 : 4

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3 : 5

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Solution

The correct option is D $4 : 21$
Let X be the distance traveled in first part and Y be the distance traveled in the second part.
Now,
X/20 + Y/70 = (X+Y)/50
(7X+2Y)/140 = (X+Y)/50
350X+100Y=140X+140Y
210X = 40Y
Now,
X/Y=40/210
X:Y=4:21

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A man travels the first part of his journey at 20 km/hr and the next at 70 km/h, covering the entire journey at an average speed of 50km/h. What is the ratio of the distance that the covered at 20 km/h to that he covered at 70km/h?

The correct option is D 4:21Let X be the distance traveled in first part and Y be the distance traveled in the second part.Now, X/20 + Y/70 = (X+Y)/50(7X+2Y)/140 = (X+Y)/50350X+100Y=140X+140Y210X = 40YNow,X/Y=40/210X:Y=4:21

A man travels the first part of his journey at $20$ km/hr and the next at $70$ km/h, covering the entire journey at an average speed of $50$ km/h. What is the ratio of the distance that the covered at $20$ km/h to that he covered at $70$ km/h?

The correct option is D $4 : 21$
Let X be the distance traveled in first part and Y be the distance traveled in the second part.
Now,
X/20 + Y/70 = (X+Y)/50
(7X+2Y)/140 = (X+Y)/50
350X+100Y=140X+140Y
210X = 40Y
Now,
X/Y=40/210
X:Y=4:21