CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
333
You visited us 333 times! Enjoying our articles? Unlock Full Access!
Question

A man tries to remain in a steady state by pushing his feet and hands against two parallel walls. Then for equilibrium:

136386_bf0a4de4216f4509bb9e7992053574d3.png

A
force of friction should be equal on the two walls
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Friction must be present on both walls
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
coefficient of friction should be equal for both walls and the man
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Friction must be present on both walls
According to Newton's third law when he applies a force on one wall, he should apply same force to the other wall for equilibrium. but the wall should not be frictionless otherwise he will fall down.
For equilibrium the forces exerted by both walls on the man should be equal so as the horizontal forces may balance but the vertical forces can be balanced even if the forces of friction on the two walls are unequal.
Ans:(B)

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Effect of Normal Force on Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon