Question

A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

• A. 3 km
• B. 4 km
• C. 5 km
• D. 7 km

Answer 1

The correct option is C 5 km



$Clearly,DF=BC=5km.$

$EF=(DE-DF)=(9-5)km=4km.$

$BF=CD=2km$

$AF=AB+BF=AB+CD=(1+2)km=3km$

$\therefore \text{Man's distance from starting point A}$

$=AE=\sqrt{A{F}^2+E{F}^2}=\sqrt{3^2+4^2}$

$=\sqrt{25}=5km$