A man walks a distance of $5$ km in $2$ hours.The he goes in a bus to a nearby town, which is $40$ km, in further $2$ hours.From there , he goes to his office in an autorickshaw, a distance of $5$ km,in $\frac{1}{2}$ hour.What was his average speed during the whole journey?

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Solution

Distance of $5$ km travelled on foot in $2$ hours.
Distance of $40$ km travelled by bus in $2$ hours.
Distance of $5$ km travelled by Rickshaw in $\frac{1}{2}$ hour.
Total distance covered $= 5 + 40 + 5 = 50$ km
Time taken $= 2 + 2 + \frac{1}{2} = 4 \frac{1}{2} = \frac{9}{2}$ hours
$∴$ Average spees $= \frac{D i s t a n c e}{T i m e} = \frac{50}{\frac{9}{2}} = \frac{100}{9} = 11 \frac{1}{9}$ kmph

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