Question

A man was 3 times as old as his son. 2 years hence twice his age will be equal to 5 times that of his son. Find their present ages.

Answer 1

Let son's present age = x
Present age of Father = 3x
Two years hence son's age= x+2.
And two years hence father's age will be 3x+2

Given :-5*(x+2)=2*(3x+2)
5x + 10= 6x + 4
10-4=6x-5x
6=x
SON'S PRESENT AGE : 6 years.

FATHER'S PRESENT AGE: 18 years

This solution is only according to your question . Don't relate it practicall as it will be against law ...hehheheheh

And this question might be like this Two years ago father was three times as old as his son two years hence twice his age will be equal to five times that of his son find their ages?
Let son's age = x
Two years ago son's age= x-2.
His Father's age at that time = 3(x-2).
Present age of Father = 3x-6+2=3x-4
Two years hence father's age=3x-4+2=3x-2.
Two years hence son's age = x+2.
Given :-5*(x+2)=2*(3x-2)
5x + 10= 6x - 4
10+4=6x-5x
14=x
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years.