Question

# A man weighs $80kg$. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5m/{s}^{2}$. What would be the reading on the scale?

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Solution

## Step 1: GivenMass of the man: $m=80kg$Acceleration of the lift: $a=5m/{s}^{2}$Acceleration due to gravity: $g=10m/{s}^{2}$ Step 2: Formula usedNormal force acting on man will be $N=m\left(g+a\right)$.Step 3: Reading on weighing scaleSubstitute the values in the formula.$N=m\left(g+a\right)\phantom{\rule{0ex}{0ex}}=80\left(10+5\right)\phantom{\rule{0ex}{0ex}}=80×15\phantom{\rule{0ex}{0ex}}=1200N$Hence, the reading on the scale will be 1200 N.

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