A manometer is connected to a flask containing a gas. The open arm reads 36.2 cm whereas the arm connected to the flask reads 15.5 cm. If the barometric pressure is 743 mm Hg, the gas pressure in atm is?

1.0 atm

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1.25 atm

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1.30 atm

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1.45 atm

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Solution

The correct option is B 1.25 atm
Given:
Difference of mercury levels in the two arms = 36.2cm -15.5cm = 20.7cm
Barometric pressure is 743 mm Hg = 74.3 cm Hg
Pressure of the gas in the bulb = Barometric pressure + Difference of mercury levels
= (74.3 cm Hg + (36.2 - 15.5) = 763.7 cm Hg
1 atm = 76 cm Hg
763.7 cm Hg = $\frac{95}{76} = 1.25 a t m$

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