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Question

Open end mercury manometer is connected to a gas chamber containing gas at a pressure of 1.38 bar. The barometric pressure is 750 mm Hg. Mercury level in the arm connected to a gas chamber stands at 11.3 cm. What is the reading in open arm of the manometer?
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Solution

Gas pressure =1.38 bar
barometric pressure =750

Arm connected to gas chamber reads 11.3 cm

Excess pressure = open arm reading - 11.3
= x-11.3 cm =(x-11.3)×10mm

Total pressure of gas = 750 + (x-11.3)×10 mm

Now 760 mm pressure =1 bar
So 1.38 bar = 1.38×760=1048.8mm
1048.8= 750+(x-11.3)×10

x=(1048.8-750+113)/10
=310.1mm
Reading in open atm of manometer =310.1mm


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