Question

A mass M is suspended by a rope from a rigid support A as shown in figure. Another rope is tied at the end B and it is pulled horizontally with a force F. If the rope AB makes an angle $\theta$ with the vertical in equilibrium, then the tension in the string AB is

• A. F sin $\theta$
• B. F/sin $\theta$
• C. F cos $\theta$
• D. F/cos $\theta$

Answer 1

Answer: (B)

F/sin $\theta$

Resolving T vertically and horizontally,
we have $Tcos\theta =Mg$ ..........(1)
$Tsin\theta =F$ ...........(2)

Now,from equation (2) we have
$T=\frac{F}{sin\theta }$
hence,option B is correct.