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Standard XII

Physics

Accelerating Containers

A mass M is s...

Question

A mass M is suspended by a rope from a rigid support at A as shown in figure. Another rope is tied at the end B and it is pulled horizontally with a force F. If the rope AB makes an angle $θ$ with the vertical, then the tension in the string AB is?

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Solution

The diagram shown in the figure elaborates about the tension in the thread.
$T s i n θ = F T = \frac{F}{s i n θ}$

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A mass M is suspended by a rope from a rigid support at A as shown in figure. Another rope is tied at the end B and it is pulled horizontally with a force F. If the rope AB makes an angle θ with the vertical, then the tension in the string AB is?

The diagram shown in the figure elaborates about the tension in the thread. Tsinθ=FT=Fsinθ

A mass M is suspended by a rope from a rigid support at A as shown in figure. Another rope is tied at the end B and it is pulled horizontally with a force F. If the rope AB makes an angle $θ$ with the vertical, then the tension in the string AB is?

The diagram shown in the figure elaborates about the tension in the thread.
$T s i n θ = F T = \frac{F}{s i n θ}$