Question

A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of the mass is $f_1$ . The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is $f_2$. Which of the following relations between the frequencies is correct?

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

When spring is cut into two equal parts then spring constant of each part will be 2K and so using $n\propto \sqrt{K}$ , new frequency will be $\sqrt{2}$ times i.e.$f_2=\sqrt{2}{f}_1$.