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Question
A mass of 0.1 kg is hung at the 20 cm mark from a 1 m rod weighing 0.25 kg pivoted at its centre. The rod will not topple if:
A mass of 0.1 kg is hung at the 20 cm mark from a 1 m rod weighing 0.25 kg pivoted at its centre. The rod will not topple if:
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Solution
The correct option is C 0.15 kg is hung at 70 cm mark
The rod will not topple if net torque about pivot is zero. Therefore one more mass should be suspended from the rod on other side of the pivot. If we take 0.1 kg mass, then it must be placed symmetrically i.e., at 80 cm mark.
Therefore, if we take 0.15kg mass, from the figure we can see that:
⇒0.1×0.3=0.15×x
⇒x=0.2m=20cm
Then, actual position is 50+20=70cm mark.
The rod will not topple if net torque about pivot is zero.
Therefore one more mass should be suspended from the rod on other side of the pivot.
If we take 0.1 kg mass, then it must be placed symmetrically i.e., at 80 cm mark.
Therefore, if we take 0.15kg mass, from the figure we can see that:
⇒0.1×0.3=0.15×x
⇒x=0.2m=20cm
⇒0.1×0.3=0.15×x
⇒x=0.2m=20cm
Then, actual position is 50+20=70cm mark.
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