Question

A mass of $10kg$ is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of ${60}^o$ with the vertical. The new reading of the balance is

• A. $20kg.wt$
• B. $10kg.wt$
• C. $10\sqrt{3}kg.wt$
• D. $20\sqrt{3}kg.wt$

Answer 1

The correct option is A $20kg.wt$

Given : $m=10kg$ $g=10m/s^2$ $\theta ={60}^o$

From FBD of the mass, $F_s\cos \theta =mg$

Or $F_s\times \frac{1}{2}=10kg.wt$

$⟹$ $F_s=20kg.wt$