A spring balance reads $10 k g$ when a bucket of water is suspended from it. What will be the reading of the balance when an iron piece of mass $7.2 k g$ suspended by a string is immersed with half its volume inside the water in the bucket? Relative density of iron is $7.2$

10 k g

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10.5 k g

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13.6 k g

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17.2 k g

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Solution

The correct option is C $10.5 k g$
Reading=weight of bucket of water+magnitude of upthrust on block
$= (10 g) + \frac{1}{2} (\frac{7.2}{7.2 ρ_{w}}) ρ_{w} g = 10.5 g = 10.5 k g$

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A spring balance reads 10kg when a bucket of water is suspended from it. What will be the reading of the balance when an iron piece of mass 7.2kg suspended by a string is immersed with half its volume inside the water in the bucket? Relative density of iron is 7.2

The correct option is C 10.5kgReading=weight of bucket of water+magnitude of upthrust on block =(10g)+12(7.27.2ρw)ρwg=10.5g=10.5kg

A spring balance reads $10 k g$ when a bucket of water is suspended from it. What will be the reading of the balance when an iron piece of mass $7.2 k g$ suspended by a string is immersed with half its volume inside the water in the bucket? Relative density of iron is $7.2$

The correct option is C $10.5 k g$
Reading=weight of bucket of water+magnitude of upthrust on block
$= (10 g) + \frac{1}{2} (\frac{7.2}{7.2 ρ_{w}}) ρ_{w} g = 10.5 g = 10.5 k g$