Question

A mass of $5$ kg is acted upon by a force of $1N$ Starting from rest , how much distance covered by the mass in $10s$?

Answer 1

Using Newton's second law , F=ma

$1=5\times a$

$a=\frac{1}{5}$

we get the acceleration to be $0.2m/s^2$.

now we know that $s=ut+\frac{1}{2}a{t}^2$

$u=0,t=10s,a=0.2m/s^2$

$\therefore s=\frac{1}{2}\ast 0.2\ast {10}^2=10m$