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Calorimetry

A mass of 50 ...

Question

A mass of $50 g$ of a certain metal at $150^{\circ} C$ is immersed in $100 g$ of water at $11^{\circ} C$ . The final temperature is $20^{\circ} C$ . Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is $4.2 J g^{- 1} K^{- 1}$ .

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Solution

Heat lost by the metal = Heat gained by water
$⟹ m_{m} S_{m} Δ T_{m} = m_{w} S_{w} Δ T_{w}$
$50 \times s_{m} \times (150 - 20) = 100 \times 4.2 \times (20 - 11)$
$s_{m} = 0.582 J g^{- 1} K^{- 1}$

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