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Question

A mass of 50 g of a certain metal at 150C is immersed in 100 g of water at 11C. The final temperature is 20 C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 J g1 K1.


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Solution

Heat lost by the metal = Heat gained by water
mmSmΔTm=mwSwΔTw
50×sm×(15020)=100×4.2×(2011)
sm=0.582 Jg1K1

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