A match box measure $4$ cm, $2.5$ cm and $1.5$ cm. What will be the volume of the packet containing 12 such boxes

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Solution

The volume of each box is $4 \times 2.5 \times 1.4 = 15 c m^{3}$ . Volume of a packet containing 12 such boxes is $15 \times 12 = 180 c m^{3}$ .

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Question 1
A matchbox measures $4 c m \times 2.5 c m \times 1.5 c m$ . What will be the volume of a packet containing 12 such boxes?

4 cm \times 2.5 cm \times 1.5 cm .

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