Question

A merchant has $140$ litres, $260$ litres and $320$ litres of three kinds of oil. He wants to sell the oil by filling the three kinds of oil separately in tins of equal volumes. The volume of such a tin is:

• A. $20$ litres
• B. $13$ litres
• C. $16$ litres
• D. $70$ litres

Answer 1

The correct option is A $20$ litres

Volume of three different kinds of oil are $140,260$ and $320$ litres.

In order to sell the oil by filling the three kinds of oil separately in tins of equal volumes, the merchant has to find the capacity of tin that divides the capacity of oil exactly.

$140=2^2\times 5\times 7$

$260=2\times 2\times 5\times 13$

$320=2^6\times 5$

$\therefore$ H.C.F $=2^2\times 5=20$ litres