Question

A mercury thermometer is transferred from melting ice to a glass of milk. The mercury level rises by three-fifth of the distance between the lower and upper fixed points. Calculate the temperature of milk (i) in $C$ is m and (ii) in $F$ is n then m+n =

Answer 1

The upper limit of thermometer is ${100}^{O}C$

Lower limit is $0^{O}C$

The difference in temperature is ${100}^{O}C$$-0^{O}C=$${100}^{O}C$

Therefore temperature of mercury is $=\left(3/5\right)\ast {100}^{O}C=$${60}^{O}C$

And in $T_F=1.8\ast T_C+32=1.8\ast 60+32=140F$

So, the value of m+n is 200