Question

A mercury thermometer is transferred from melting ice to a hot liquid. The mercury rises to $9/10$ of the distance between the two fixed points. Find the temperature of the liquid in Fahrenheit scale.

• A. ${197}^{\circ }F$
• B. ${162}^{\circ }F$
• C. ${112}^{\circ }F$
• D. ${113}^{\circ }F$

Answer 1

The correct option is A ${197}^{\circ }F$

$\frac{9}{10(100-0)}=90°C.$ For converting to$°F.$

$\frac{C-0}{100}=\frac{F-32}{180}$

$\frac{90}{100}=\frac{F-32}{180}$

$F=197°F$