Question

A mercury thermometer is transferred from melting ice to a hot liquid. The mercury rises to $\frac{9}{10}$ of the distance between the two fixed points. Find the temperature of the liquid in Faherenheit scale

• A. ${194}^{\circ }F$
• B. ${162}^{\circ }F$
• C. ${112}^{\circ }F$
• D. ${113}^{\circ }F$

Answer 1

The correct option is A ${194}^{\circ }F$

The mercury rises to 9/10 of the distance between the two fixed points.

Now from the conversion formula we can get,
$\frac{F-32}{180}=\frac{9}{10}$.

So, the temperature of the liquid in Faherenheit scale is= ${194}^{o}F$