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Phase Change

A metal ball ...

Question

A metal ball of mass 0.5 kg and at 900°c is placed on a block of ice,till it attains the temp. of ice. If the S.H.C. of metal ball is 850 J/Kg/K, calculate the amount of ice, which melts.(Take sp. latent heat of ice = 34X10 raise to the power 4 J/kg)

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Solution

Dear Student

$Q_{h e a t g a i n e d b y i c e} = Q_{h e a t l o s t b y m e t a l b a l l} m_{i c e} L = m_{m e t a l b a l l} c ∆ T m_{i c e} = \frac{m_{m e t a l b a l l} c ∆ T}{L} m_{i c e} = \frac{(0.5) (850) (900 - 0)}{34 \times 10^{4}} m_{i c e} = 1.125 k g$
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