Question

A 2 kg copper block is heated to 500${}^o$C and then it is placed on a large block of ice at 0${}^o$C. If the specific heat capacity of copper is 400 J/kg/C and latent heat of water is $3.5\times {10}^{5}J/kg$. The amount of ice that can melt is:

• A. 7/8 kg
• B. 7/5 kg
• C. 8/7 kg
• D. 5/7 kg

Answer 1

The correct option is C 8/7 kg

Let $m_{ice}$ kg of ice melt heat lost by copper = heat gained by ice

$\therefore$ $M_{cu}S\left(\Delta T\right)=m_{ice}L$
$2\times 400\times (500-0)=m_{ice}\times 3.5\times {10}^5$
$m_{ice}=\frac{2\times 400\times 500}{3.5\times {10}^5}=\frac{8}{7}kg$