A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is $‘ a^{'}$ , the closest approach between two atoms in a metallic crystal will be:

2 \sqrt{2} a

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\sqrt{2} a

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\frac{a}{\sqrt{2}}

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Solution

The correct option is C $\frac{a}{\sqrt{2}}$
In FCC structure

$4 r = \sqrt{2} a$

$2 r = \frac{a}{\sqrt{2}} =$ closest approach between two atoms.

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A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is ‘a′, the closest approach between two atoms in a metallic crystal will be:

The correct option is C a√2In FCC structure 4r=√2a 2r=a√2= closest approach between two atoms.

A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is $‘ a^{'}$ , the closest approach between two atoms in a metallic crystal will be:

The correct option is C $\frac{a}{\sqrt{2}}$
In FCC structure

$4 r = \sqrt{2} a$

$2 r = \frac{a}{\sqrt{2}} =$ closest approach between two atoms.