Question

A metal cube is completely submerged in a cylindrical vessel containing water. The radius of the vessel is 5 cm, the level of water is raised by $\frac{140}{11}cm$. The volume of the cube is (in $c{m}^3$)

• A. 100
• B. 1000
• C. 400
• D. 27000

Answer 1

The correct option is B 1000


Radius of the cylindrical vessel, r = 5 cm

Level of water raised, $h=\frac{140}{11}cm$

Volume of the cube submerged = Volume of the water raised in the cylinder

$=\pi r^{2}h$

$=\frac{22}{7}\times (5{)}^2\times \frac{140}{11}$

$=\frac{22\times 25\times 140}{7\times 11}$

= 2 × 25 × 20

$=1000c{m}^3$

Hence, the correct answer is option (b)