Question

A metal has a $bcc$ structure and the edge length of its cell is $3.04\stackrel{\circ }{A}$. The volume of the unit cell in $c{m}^3$ will be:

• A. $1.6\times {10}^{-21}$
• B. $2.81\times {10}^{-23}$
• C. $6.02\times {10}^{-23}$
• D. $6.6\times {10}^{-24}$

Answer 1

The correct option is B $2.81\times {10}^{-23}$

As we know, volume of the unit cell $=a^3$ (where a is the unit length)

Volume $=(3.04\times {10}^{-8}{)}^3=2.81\times {10}^{-23}$ cm${}^3$

B is correct