A metal $X$ displaces nickel from nickel sulphate solution but does not displace manganese from manganese sulphate solution. What is the correct order of their reducing powers?

N i > M n > X

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X > M n > N i

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M n > X > N i

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M n > N i > X

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Solution

The correct option is C $M n > X > N i$
Given that:
$X + N i S O_{4} \to N i + X_{2} (S O_{4})_{n}$
and $X + M n S O_{4} \to N o r e a c t i o n$
Thus $N i^{2 +}$ has higher reduction potential than $X$ while $M n^{2 +}$ has lower reduction potential than $X$ .
Reduction potential is the ease of gaining electron by the salt of metal ions and get reduced to respective metal.
Since $X$ can displace $N i^{2 +}$ , its reducing power is higher than $N i$ metal and $X$ cannot displace $M n^{2 +}$ , its reducing power is lower than $M n$ metal.
Order of reducing power of the metals are thus:
$M n > X > N i$

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