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Question

# A metallic block of mass 20 kg is dragged with a uniform velocity of 0.5 ms−1 on a horizontal table for 2.1 s. The coefficient of static friction between the block and the table is 0.10. What will be the maximum possible rise in temperature of the metal block, if the specific heat of the block is 0.1 C.G.S. unit? Assume g=10 ms−1 and uniform rise in temperature throughout the whole block. [Ignore absorption of heat by the table]

A
0.0025 oC
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B
0.0035 oC
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C
0.001 oC
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D
0.05 oC
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Solution

## The correct option is A 0.0025 oCW=FS=(μmg)vtW=0.1×20×10×0.5×2.1=21 J This work done by friction is converted into heat energy: ∴Q=21 JQ=20×103×4200×Δθ [as S=0.1×4200 J/kg−K] ⇒Δθ=0.0025 K=0.0025 oC

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