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Question

# A microphone having a DC level of zero drives a CG stage biased in saturation region at ID=0.5mA. If (WL)=50, μnCox=100μAV2, VTh=0.5V and VDD=1.8V assuming negligible channel length modulation then

A
The maximum value of voltage gain is equal to 6.06V/V
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B
The maximum value of RD=2.71kΩ
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C
The minimum value of RD=7.21kΩ
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D
The value of VGS=0.947V
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Solution

## The correct option is D The value of VGS=0.947VID=12μnCoxWL(VGS–VTh)2 0.5×10−3=12×100×10−6×(50)(VGS–0.5)2 VGS–VTh=0.4472V VGS=0.947V For the transistor to remain in saturation VDD–IDRD>VGS–VTh And hence, RD<2.71kΩ Also, the above value of (WL) and ID yield δm=√μnCax(WL)×2ID=0.00223Ω AV≤δmRD AV≤6.06 →(AV)max=6.06

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