A microscope is focused on a coin lying at the bottom of a beaker. The microscope is now raised up by 1 cm. To what depth should the water be poured into the beaker so that coin is again in focus? (Refractive index of water is $\frac{4}{3}$ )

1 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 4 cm
Water should be poured to a height $h$ cm so that apparent shift in position of coin is $1$ cm.

As $y = (1 - \frac{1}{n}) h$

$\Rightarrow h = \frac{y}{(1 - \frac{1}{n})} = \frac{1}{(1 - \frac{1}{4 / 3})} = \frac{1}{\frac{1}{4}} = 4 c m$

Suggest Corrections

Similar questions

Q. A microscope is focussed on a coin lying at the bottom of a beaker. The microscope is now raised by 1 cm. To what depth should water be poured into the beaker so that the coin is again in focus? (The refractive index of water is

\frac{4}{3}

Q. A microscope is focussed on a coin lying at the bottom of a beaker. The microscope is now raised up by

1 c m

. To what depth should the water be poured in to the beaker so that coin is again in focus

(μ_{w} = \frac{4}{3}

)

A coin is kept at bottom of an empty beaker. A traveling microscope is focussed on the coin from the top, now water is poured into beaker up to a height of $10 c m$ . By what distance and in which direction should the microscope be moved to bring the coin again in focus

Q. A mark is made on the bottom of a beaker and a microscope is focused on it . The microscope is raised through 1.5 cm . To what height water must be poured into the beaker to bring the mark again into focus ? Given that 'n' is 4/3

Q. A travelling microscope is focussed on to a scratch on the bottom of a beaker. Water of refractive index is

\frac{4}{3}

poured in it. Then the microscope is to be lifted through

2 c m

focus it again. Find the depth of the water in the beaker.

Join BYJU'S Learning Program

A microscope is focused on a coin lying at the bottom of a beaker. The microscope is now raised up by 1 cm. To what depth should the water be poured into the beaker so that coin is again in focus? (Refractive index of water is 43)

The correct option is D 4 cmWater should be poured to a height h cm so that apparent shift in position of coin is 1 cm.As y=(1−1n)h⇒h=y(1−1n)=1(1−14/3)=114=4cm

A microscope is focused on a coin lying at the bottom of a beaker. The microscope is now raised up by 1 cm. To what depth should the water be poured into the beaker so that coin is again in focus? (Refractive index of water is $\frac{4}{3}$ )

The correct option is D 4 cm
Water should be poured to a height $h$ cm so that apparent shift in position of coin is $1$ cm.

As $y = (1 - \frac{1}{n}) h$

$\Rightarrow h = \frac{y}{(1 - \frac{1}{n})} = \frac{1}{(1 - \frac{1}{4 / 3})} = \frac{1}{\frac{1}{4}} = 4 c m$