A microscope is focused on a mark, then a glass slab of refractive index $1.5$ and thickness of $3$ cm is placed on the mark to get the mark again in focus, the microscope should be moved

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2$ cm
Given,
$μ = 1.5$
Real depth, $h = 3 c m$
lets consider, $h^{'} =$ apparent depth
The refractive index is the ratio of real depth and the apparent depth,
$μ = \frac{h}{h^{'}}$
$h^{'} = \frac{h}{μ} = \frac{3 c m}{1.5} = 2 c m$
The correct option is B.

Suggest Corrections

Similar questions

Q. A microscope is focused on a mark on a piece of paper and then a slab of glass of thickness 3 cm and refractive index 1.5 is placed over the mark. How should the microscope be moved to get the mark in focus again ?

Q. A microscope is focussed on a mark on a piece of paper and then a slab of glass of thickness

3 cm

and refractive index

1.5

is placed over the mark. How should the microscope be moved to get the mark in focus again?

A microscope is focused on an ink mark on the top of a table. If we place a glass slab 3cm thick on it, how should the microscope be moved to focus the ink spot again? The refractive index of glass slab is 1.5 cm.

Q. A microscope is focussed on an ink mark on the top of a table. If we place a glass slab of

3

cm thick on it, how should the microscope be moved to focus the ink spot again? The refractive index of glass is

1.5

Q. A mark is made on the bottom of a beaker and a microscope is focused on it . The microscope is raised through 1.5 cm . To what height water must be poured into the beaker to bring the mark again into focus ? Given that 'n' is 4/3

Join BYJU'S Learning Program

A microscope is focused on a mark, then a glass slab of refractive index 1.5 and thickness of 3 cm is placed on the mark to get the mark again in focus, the microscope should be moved

The correct option is B 2cmGiven,μ=1.5Real depth, h=3cmlets consider, h′= apparent depthThe refractive index is the ratio of real depth and the apparent depth,μ=hh′h′=hμ=3cm1.5=2cmThe correct option is B.

A microscope is focused on a mark, then a glass slab of refractive index $1.5$ and thickness of $3$ cm is placed on the mark to get the mark again in focus, the microscope should be moved

The correct option is B $2$ cm
Given,
$μ = 1.5$
Real depth, $h = 3 c m$
lets consider, $h^{'} =$ apparent depth
The refractive index is the ratio of real depth and the apparent depth,
$μ = \frac{h}{h^{'}}$
$h^{'} = \frac{h}{μ} = \frac{3 c m}{1.5} = 2 c m$
The correct option is B.