Question

A milkman has two types of milk. In the first container, the percentage of milk is 80% and in the second container, the percentage of milk is 60%. If he mixes 28 litres of milk of the first container to the 32 litres of milk of the second container, then the percentage of milk in the mixture is:

• A. 63.99
• B. 69.33
• C. 72.5
• D. 75.2

Answer 1

The correct option is B 69.33


So $(80-60)\times \frac{7}{7+8}=20\times \frac{7}{15}=9.33$
Thus the required percentage = 60 + 9.33 = 69.33