Question

There are two mixtures such that they contain 75% milk and 80% milk respectively. Some amount from first mixture is mixed with twice the same amount of second mixture. Find the percentage of milk in the resultant mixture

Answer 1

Let some amount $x$ is taken from first mixture

Then amount taken from second mixture = $2x$

Let the percentage of milk in resultant mixture be $p$%

According to question , $x\times \frac{3}{4}+2x\times \frac{4}{5}$=$3x\times \frac{p}{100}$

Solving we get $y=\frac{235}{3}$%