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Resistance of P-N Junction

A milliammete...

Question

A milliammeter reading from 0 to 50 mA has a resistance of 396 ohm. How will you change it so that it can be used as an ammeter to measure a maximum current of 5A?

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Solution

Given : $I_{g} = 50 m A = 0.05 A$ $R_{g} = 396 Ω$
Maximum current $I = 5 A$
So, $I = I_{g} (1 + \frac{R_{g}}{R_{s}})$
Or $5 = 0.05 \times (1 + \frac{396}{R_{s}})$
Or $R_{s} = 4 Ω$
Thus a $4 Ω$ shunt resistance is to be used in parrallel to galvanometer to convert it into an ammeter.

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