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Relationship between Vapor Density & Relative Molecular Mass

A mixture con...

Question

A mixture contains $N_{2} O_{4}$ and $N O_{4}$ in $2 : 1$ ratio by volume. The vapour density of the mixture is:

45.4

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49.8

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32.6

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38.3

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Solution

The correct option is D $38.3$
Vapour density $N_{2} O_{4}$ = $\frac{m o l a r m a s s N_{2} O_{4}}{m o l a r m a s s H_{2}}$ = $92.011 / 2.016 = 45.64$

vapour density $N O_{2}$ = $\frac{m o l a r m a s s N O_{2}}{m o l a r m a s s H_{2}}$ = $\frac{46.0055}{2.016} = 22.82$

The ratio is 2:1 in favour $N_{2} O_{4}$ ; therefore,

v.d. of $N_{2} O_{4} \times 2 =$ 91.28

+ v.d. $N O_{2} \times 1 =$ 22.82
sum is 114.1

Average is 114.1/3 = 38.33

Hence, the correct option is D.

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