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Question

# The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27'C. Calculate moles of NO2 in 100 g of mixture.

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Solution

## Vapour desity concept Weight of a unit volume of gas or vapor compared to (divided by) the weight of an equal volume of air (or, sometimes, hydrogen) vapour density = mass of n molecules of gas / mass of n molecules of hydrogen vapour density = molar mass of gas / molar mass of H2 vapour density = molar mass of gas / 2.01 Vapour density of gas = molar mass /2.01 Molar mass of gas mixture = 38.3*2.01= 77 Total Moles / 100 gm gas = 100/77 =1.3 moles Let n is NO2 moles (1.3-n ) = N2O4 moles Mol wt of NO2 = 46 Mol wt of N2O4 = 92 n*46+ (1.3-n)*92=100 n=0.42 Therefore the given 100gm gas has following composition NO2 = 0.42 moles or 0.42*46= 19.32 gms N2O4=0.88 moles or 0.88*92 = 19.342 gms

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