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Question

# The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 300 K. The number of moles of NO2 in 100 g of the mixture is approximate:

A
0.44
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B
4.4
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C
33.4
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D
3.34
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Solution

## The correct option is B 0.44Let us asssume that x moles of NO2 in mixture.Hence, there will be (100−x) moles of N2O4 in mixture . (since total no. of moles is 100.)1 mole of NO2 weight 46g=(14+2×16)gms1 mole of N2O4 weight 92g=(2×14+4×16)gmsTotal molecular mass of mixturee =(x)(46)+(100−x)92We know that, Molecular mass=2(vapordensity)=2×(38.3)=76.6gMolar mass of mixture=massofmixturetotalno.ofmoles76.6=46x+(100−x)92100(100−x)92+46x=7660x=33.4833.48 moles of NO2 are in mixture.

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