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Ideal Gas Equation

A mixture of ...

Question

A mixture of $0.84 g$ of $N a H {C O}_{3}$ , $4.0 g$ of $N a O H$ and $10.6 g$ of ${N a}_{2} {C O}_{3}$ is dissolved in $100 m l$ $H_{2} O$ . The solution obtained is thus titrated with $0.5 M$ $H C l$ solution. Which of the following option is/are correct?

The volume of

H C l

used at phenolphthalein end point is

400 m l

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The volume of

H C l

used at methyl orange end point is

400 m l

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The volume of

H C l

used at methyl orange end point after phenolphthalein end point is

220 m l

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The volume of

H C l

used at phenolphthalein end point after phenolphthalein end point is

220 m l

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Solution

The correct option is A The volume of $H C l$ used at phenolphthalein end point is $400 m l$

$0.84 g N a {H C O}_{3} = 0.01$ moles
$4 g N a O H = 0.1$ moles
$10.6 {N a}_{2} {C O}_{3} = 0.1$ moles
with phenolhthalein indicator we can detect until $N a O H$ consumed and ${N a}_{2} {C O}_{3} \to {N a H C O}_{3}$ conversion.
Hence $\Rightarrow 0.2$ moles of acid needed
$0.2 = 0.5 \times V_{l i t} V_{l i t} = 0.4 l i t$
$= 400 m l$
With methyl orange we detect total conversion
$\Rightarrow (0.1) + (0.01) + (0.1) \times 2 = 0.31$
$0.31 = 0.5 M \times v_{l i t}$
$v_{l i t} = 0.62$ lit
$= 620 m l$

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Similar questions

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A mixture of 0.84g of NaHCO3, 4.0g of NaOH and 10.6g of Na2CO3 is dissolved in 100ml H2O. The solution obtained is thus titrated with 0.5M HCl solution. Which of the following option is/are correct?

A mixture of $0.84 g$ of $N a H {C O}_{3}$ , $4.0 g$ of $N a O H$ and $10.6 g$ of ${N a}_{2} {C O}_{3}$ is dissolved in $100 m l$ $H_{2} O$ . The solution obtained is thus titrated with $0.5 M$ $H C l$ solution. Which of the following option is/are correct?